Cubed Identities in Algebra
🎯 What will you learn at the end of this chapter?
👉 The formulas related to (a + b)³ and (a − b)³ and their explanations.
👉 How to solve problems using the formulas for (a + b)³ and (a − b)³.
👉 Other important formulas derived from (a + b)³ and (a − b)³.
👉 The derivation and proof of cubed identities in algebra.
🔹 In algebra, identities whose highest power is 3 are called cubed identities.
🔹 An identity is an equality that remains true for all permissible values of its variables. Here a and b are variables.
🔹 These identities are widely used in algebra and in many other branches of mathematics.
🔹 They are commonly used to simplify algebraic expressions and to factorise them.
✍ Practice Problems Based on the Identities Above
🔹 01. What is the value of ?
🔹 02. Simplify (2x + 3y)3 + 3(2x + 3y)2(y − 2x) + 3(2x + 3y)(y − 2x)2 + (y − 2x)3 using an identity.
🔹 03. If , find .
🔹 04. If , find .
🔹 05. If x + y = 1, find x3 + y3 + 3xy.
🔹 06. If , find x3 + 27.
🔹 07. If , find .
🔹 08. If a + b = 0, find a3 + b3.
🔹 09. Expand (a + b){(2a − b)2 + (2a − b)(a − 2b) + (a − 2b)2} using an identity.
🔹 10. If , find .
🔹 11. If m + n = − 2, find m3 + n3 − 6mn.
👉 Click here to see the step-by-step solutions to these problems.
✍ Practice Problems Based on the Identities Above
🔹 12. Find the value of (x + y)3 + (x − y)3.
🔹 13. If x2 − 2x − 1 = 0, find .
🔹 14. Find the simplest value of .
🔹 15. If x3 + 3x2 + 3x = 7, find x3 − 3x2 + 3x.
🔹 16. If , find .
🔹 17. If a = b + c, prove that a3 − b3 − c3 = 3abc.
🔹 18. If a − b = 1 and a3 − b3 = 61, find ab.
🔹 19. If a + b = 5, ab = 4, and a > b, find (a2 + b2)(a3 − b3).
🔹 20. If x = 0.25, find 64x3 + 144x2 + 108x + 30 using an identity.
🔹 21. If a − b = 8, find a3 − b3 − 24ab using an identity.
🔹 22. If , find .
🧠 Quick Revision
⭐ (a + b)³ = a³ + 3a²b + 3ab² + b³
⭐ (a + b)³ = a³ + b³ + 3ab(a + b)
⭐ a³ + b³ = (a + b)³ - 3ab(a + b)
⭐ a³ + b³ = (a + b)(a² - ab + b²)
⭐ (a - b)³ = a³ - 3a²b + 3ab² - b³
⭐ (a - b)³ = a³ - b³ - 3ab(a - b)
⭐ a³ - b³ = (a - b)³ + 3ab(a - b)
⭐ a³ - b³ = (a - b)(a² + ab + b²)