Let the expression be f(x) = ax³ + bx + c. We need to determine the value of x for which f(x) becomes 0 (zero).

If the value of the expression becomes zero when X = m, then (x – m) will be a factor of the expression.

∵ x³ – 3x + 2

Let f(x) = x³ – 3x + 2. Substituting x= 1,

∴ f(1) = 1³ – 3.1 + 2 = 0

The value of the function will be 0 (zero).

∵ x= 1

or, (x − 1) = 0

🔹 x³ – 3x + 2

= x³ – x² + x² – x – 2x + 2

= x²(x – 1) + x(x – 1) – 2(x – 1)

= (x – 1) (x² + x – 2)

= (x – 1){x² + (2 – 1)x – 2}

= (x – 1){x² + 2x – 1x – 2}

= (x – 1){x(x + 2) – (x + 2)}

= (x – 1)²(x + 2)